Entwurf

Version 8.5 von Torben Würth am 2024/02/06 15:20

Vektoren

Zeichne ein zweidimensionales Koordinatensystem und ermittle zeichnerisch \(\vec{a}+\vec{b}\)
a)  
\(\vec{a}= \left(\begin{array}{c}1\\3 \end{array}\right)\) ; \(\vec{b}= \left(\begin{array}{c}2\\4 \end{array}\right)\)
b)
\(\vec{a}= \left(\begin{array}{c}-1\\2 \end{array}\right)\) ; \(\vec{b}= \left(\begin{array}{c}3\\-4 \end{array}\right)\)

AFB I - K5Quelle Torben Würth

Zeichne ein zweidimensionales Koordinatensystem und ermittle zeichnerisch \(\vec{a}+\vec{b}+\vec{c}\)
a)  
\(\vec{a}= \left(\begin{array}{c}2\\3 \end{array}\right)\) ; \(\vec{b}= \left(\begin{array}{c}4\\1 \end{array}\right)\) ; \(\vec{c}= \left(\begin{array}{c}-1\\2 \end{array}\right)\)
b)
\(\vec{a}= \left(\begin{array}{c}-2\\2 \end{array}\right)\) ; \(\vec{b}= \left(\begin{array}{c}3\\-4 \end{array}\right)\) \(\vec{c}= \left(\begin{array}{c}3\\3\end{array}\right)\)

AFB I - K5Quelle Torben Würth

Berechne
a)  
\(\left(\begin{array}{c}12\\7 \end{array}\right)+\left(\begin{array}{c}2\\4 \end{array}\right)=\)
b)
\(\left(\begin{array}{c}-16\\33 \end{array}\right)+\left(\begin{array}{c}0,5\\-33 \end{array}\right)=\)
c)  
\(\left(\begin{array}{c}-1,5\\\frac{1}{3} \end{array}\right)+\left(\begin{array}{c}\sqrt{2}\\\pi\end{array}\right)=\)
d)  
\(\left(\begin{array}{c}\frac{1}{2}\sqrt{2}\\5\pi \end{array}\right)-\left(\begin{array}{c}\sqrt{2}\\\pi\end{array}\right)=\)
e)  
\(\left(\begin{array}{c}\frac{3}{7}\\\5 \end{array}\right)+\left(\begin{array}{c}\frac{5}{7}\\5 \end{array}\right)-\left(\begin{array}{c}\frac{1}{7}\\\5 \end{array}\right)=\)
 
f)
\(\left(\begin{array}{c}1\\7\\9 \end{array}\right)+\left(\begin{array}{c}2\\4\\-1 \end{array}\right)=\)
g)
\(\left(\begin{array}{c}100\\71\\92 \end{array}\right)+\left(\begin{array}{c}203\\4\\-119\end{array}\right)=\)
h)
\(\left(\begin{array}{c}12,6\\8,1\\0,3\end{array}\right)-\left(\begin{array}{c}-0,6\\0,9\\\frac{1}{3}\end{array}\right)=\)

AFB I - K5Quelle Torben Würth